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First, we need to know the
probability of each combination:
A) 0.45 x 0.45 x 0.55 =
0.13613 = 13.61%
B) 0.45 x 0.55 x 0.45 =
0.13613 = 13.61%
C) 0.55 x 0.45 x 0.45 =
0.13613 = 13.61%
Then, the probability of
two males in the next three new born is:
0.1361 + 0.1361 + 0.1361 =
0.4083 = 40.83%
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