Then, we should calculate the mean scores in each of two categories of the binary variable.

With hypertension = (1 x18) + (2 x 54) + (3 x 78)/150= 2.4

Without hypertension = (1 x 100) + (2 x 112) + (3 x 98) /310 =1.99

In addition we need to calculate the overall mean score and standard deviation for the scores of the two groups.

Overall mean score = (1 x 118) + (2 x 166) + (3 x 176)/460 = 2.13

S= √(1-213)2 + (2-2.13)2 + (3-2.13)2 / 460-2 = 0.067